Integrand size = 15, antiderivative size = 81 \[ \int x \sqrt {b x+c x^2} \, dx=-\frac {b (b+2 c x) \sqrt {b x+c x^2}}{8 c^2}+\frac {\left (b x+c x^2\right )^{3/2}}{3 c}+\frac {b^3 \text {arctanh}\left (\frac {\sqrt {c} x}{\sqrt {b x+c x^2}}\right )}{8 c^{5/2}} \]
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Time = 0.02 (sec) , antiderivative size = 81, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.267, Rules used = {654, 626, 634, 212} \[ \int x \sqrt {b x+c x^2} \, dx=\frac {b^3 \text {arctanh}\left (\frac {\sqrt {c} x}{\sqrt {b x+c x^2}}\right )}{8 c^{5/2}}-\frac {b (b+2 c x) \sqrt {b x+c x^2}}{8 c^2}+\frac {\left (b x+c x^2\right )^{3/2}}{3 c} \]
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Rule 212
Rule 626
Rule 634
Rule 654
Rubi steps \begin{align*} \text {integral}& = \frac {\left (b x+c x^2\right )^{3/2}}{3 c}-\frac {b \int \sqrt {b x+c x^2} \, dx}{2 c} \\ & = -\frac {b (b+2 c x) \sqrt {b x+c x^2}}{8 c^2}+\frac {\left (b x+c x^2\right )^{3/2}}{3 c}+\frac {b^3 \int \frac {1}{\sqrt {b x+c x^2}} \, dx}{16 c^2} \\ & = -\frac {b (b+2 c x) \sqrt {b x+c x^2}}{8 c^2}+\frac {\left (b x+c x^2\right )^{3/2}}{3 c}+\frac {b^3 \text {Subst}\left (\int \frac {1}{1-c x^2} \, dx,x,\frac {x}{\sqrt {b x+c x^2}}\right )}{8 c^2} \\ & = -\frac {b (b+2 c x) \sqrt {b x+c x^2}}{8 c^2}+\frac {\left (b x+c x^2\right )^{3/2}}{3 c}+\frac {b^3 \tanh ^{-1}\left (\frac {\sqrt {c} x}{\sqrt {b x+c x^2}}\right )}{8 c^{5/2}} \\ \end{align*}
Time = 0.43 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.19 \[ \int x \sqrt {b x+c x^2} \, dx=\frac {\sqrt {x (b+c x)} \left (\sqrt {c} \left (-3 b^2+2 b c x+8 c^2 x^2\right )+\frac {6 b^3 \text {arctanh}\left (\frac {\sqrt {c} \sqrt {x}}{-\sqrt {b}+\sqrt {b+c x}}\right )}{\sqrt {x} \sqrt {b+c x}}\right )}{24 c^{5/2}} \]
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Time = 2.43 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.90
method | result | size |
risch | \(-\frac {\left (-8 c^{2} x^{2}-2 b c x +3 b^{2}\right ) x \left (c x +b \right )}{24 c^{2} \sqrt {x \left (c x +b \right )}}+\frac {b^{3} \ln \left (\frac {\frac {b}{2}+c x}{\sqrt {c}}+\sqrt {c \,x^{2}+b x}\right )}{16 c^{\frac {5}{2}}}\) | \(73\) |
default | \(\frac {\left (c \,x^{2}+b x \right )^{\frac {3}{2}}}{3 c}-\frac {b \left (\frac {\left (2 c x +b \right ) \sqrt {c \,x^{2}+b x}}{4 c}-\frac {b^{2} \ln \left (\frac {\frac {b}{2}+c x}{\sqrt {c}}+\sqrt {c \,x^{2}+b x}\right )}{8 c^{\frac {3}{2}}}\right )}{2 c}\) | \(79\) |
pseudoelliptic | \(\frac {8 c^{\frac {5}{2}} \sqrt {x \left (c x +b \right )}\, x^{2}+2 b \,c^{\frac {3}{2}} x \sqrt {x \left (c x +b \right )}+3 \,\operatorname {arctanh}\left (\frac {\sqrt {x \left (c x +b \right )}}{x \sqrt {c}}\right ) b^{3}-3 b^{2} \sqrt {c}\, \sqrt {x \left (c x +b \right )}}{24 c^{\frac {5}{2}}}\) | \(79\) |
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Time = 0.28 (sec) , antiderivative size = 148, normalized size of antiderivative = 1.83 \[ \int x \sqrt {b x+c x^2} \, dx=\left [\frac {3 \, b^{3} \sqrt {c} \log \left (2 \, c x + b + 2 \, \sqrt {c x^{2} + b x} \sqrt {c}\right ) + 2 \, {\left (8 \, c^{3} x^{2} + 2 \, b c^{2} x - 3 \, b^{2} c\right )} \sqrt {c x^{2} + b x}}{48 \, c^{3}}, -\frac {3 \, b^{3} \sqrt {-c} \arctan \left (\frac {\sqrt {c x^{2} + b x} \sqrt {-c}}{c x}\right ) - {\left (8 \, c^{3} x^{2} + 2 \, b c^{2} x - 3 \, b^{2} c\right )} \sqrt {c x^{2} + b x}}{24 \, c^{3}}\right ] \]
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Time = 0.26 (sec) , antiderivative size = 117, normalized size of antiderivative = 1.44 \[ \int x \sqrt {b x+c x^2} \, dx=\begin {cases} \frac {b^{3} \left (\begin {cases} \frac {\log {\left (b + 2 \sqrt {c} \sqrt {b x + c x^{2}} + 2 c x \right )}}{\sqrt {c}} & \text {for}\: \frac {b^{2}}{c} \neq 0 \\\frac {\left (\frac {b}{2 c} + x\right ) \log {\left (\frac {b}{2 c} + x \right )}}{\sqrt {c \left (\frac {b}{2 c} + x\right )^{2}}} & \text {otherwise} \end {cases}\right )}{16 c^{2}} + \sqrt {b x + c x^{2}} \left (- \frac {b^{2}}{8 c^{2}} + \frac {b x}{12 c} + \frac {x^{2}}{3}\right ) & \text {for}\: c \neq 0 \\\frac {2 \left (b x\right )^{\frac {5}{2}}}{5 b^{2}} & \text {for}\: b \neq 0 \\0 & \text {otherwise} \end {cases} \]
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Time = 0.19 (sec) , antiderivative size = 85, normalized size of antiderivative = 1.05 \[ \int x \sqrt {b x+c x^2} \, dx=-\frac {\sqrt {c x^{2} + b x} b x}{4 \, c} + \frac {b^{3} \log \left (2 \, c x + b + 2 \, \sqrt {c x^{2} + b x} \sqrt {c}\right )}{16 \, c^{\frac {5}{2}}} - \frac {\sqrt {c x^{2} + b x} b^{2}}{8 \, c^{2}} + \frac {{\left (c x^{2} + b x\right )}^{\frac {3}{2}}}{3 \, c} \]
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Time = 0.27 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.88 \[ \int x \sqrt {b x+c x^2} \, dx=\frac {1}{24} \, \sqrt {c x^{2} + b x} {\left (2 \, {\left (4 \, x + \frac {b}{c}\right )} x - \frac {3 \, b^{2}}{c^{2}}\right )} - \frac {b^{3} \log \left ({\left | 2 \, {\left (\sqrt {c} x - \sqrt {c x^{2} + b x}\right )} \sqrt {c} + b \right |}\right )}{16 \, c^{\frac {5}{2}}} \]
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Time = 0.09 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.85 \[ \int x \sqrt {b x+c x^2} \, dx=\frac {b^3\,\ln \left (\frac {b+2\,c\,x}{\sqrt {c}}+2\,\sqrt {c\,x^2+b\,x}\right )}{16\,c^{5/2}}+\frac {\sqrt {c\,x^2+b\,x}\,\left (-3\,b^2+2\,b\,c\,x+8\,c^2\,x^2\right )}{24\,c^2} \]
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